The number of positive integral solutions of 15<x1+x2+x3≤20, is equal to
785
685
1150
None of these
We have, 15<x1+x2+x3≤20
⇒ x1+x2+x3=16+r,r=0,1,2,3,4.
Now, number of positive integral solutions of x1+x2+x3=16+r is C3−1 16+r−1=C2 15+r
Thus, total number of solutions
=∑r=04 15+rC2=15C2+16C2+17C2+18C2+19C2=20C3−15C3=685