Number of positive integral values of b for which the origin and the point (1,1) lie on the same side of the straight line, a2x+aby+1=0∀a∈R is
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a
0
b
1
c
2
d
3
answer is B.
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Detailed Solution
(0,0) and (1,1) lie on same side of line a2x+aby+1=0 For (0,0),L:a2(0)+ab(0)+1>0∴ for (1,1), we must have a2+ab+1>0 ∀a∈R∴ D<0∴ b2−4<0⇒ b∈(−2,2) but b>0⇒b∈(0,2)The number of integral values taken by b is 1 ie; b=1