The number of positive solutions satisfying the equation tan−112x+1+tan−114x+1=tan−12x2, is
1
2
8
9
We have,
tan−112x+1+tan−114x+1=tan−12x2⇒ tan−112x+1+14x+11−1(2x+1)(4x+1)=tan−12x2⇒ tan−13x+14x2+3x=tan−12x2⇒ 3x+14x2+3x=2x2⇒3x2−7x−6=0⇒x=−23,3