The number of possible outcomes in a throw of n ordinary dice in which at least one of the dice shows an odd number is
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a
6n-1
b
3n-1
c
6n-3n
d
none of these
answer is C.
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Detailed Solution
The total number of ways is 6 × 6 × ... to n times = 6n. The total number of ways to show only even numbers is 3 × 3 × …. to n times = 3n. Therefore, the required number of ways is 6n - 3n.