The number of possible outcomes in a throw of n ordinary dice in which at least one of the dice shows on odd number is
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a
6n−1
b
3n−1
c
6n−3n
d
nP6− nP3
answer is C.
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Detailed Solution
The number of outcomes of n dice =6×6×......n times=6n The number of outcomes when there is no odd number (all even number) on any die =3×3×3×......n times=3n ∴ The number of outcomes in which at least one of the dice shows an odd number =6n−3n