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Q.

The number of possible outcomes in a throw of n ordinary dice in which at least one of the dice shows on odd number is

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a

6n−1

b

3n−1

c

6n−3n

d

nP6− nP3

answer is C.

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Detailed Solution

The number of outcomes of n dice =6×6×......n  times=6n The number of outcomes when there is no odd number (all even number) on any die =3×3×3×......n  times=3n ∴  The number of outcomes in which at least one of the dice shows an odd number =6n−3n
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