Questions
The number of real roots of the equation is
a
6
b
8
c
4
d
0
detailed solution
Correct option is C
The given equation becomes sinθ+cosθ=15sinθcosθ Squaring, 1+sin2θ=15sin2θcos2θ1+sin2θ=154sin22θ⇒15sin22θ−4sin2θ−4=0⇒ sin2θ=23,−25As θ varies from 0 to π,2θ varies from θ to 2π.Corresponding to sin 2θ=23,there are two solutions.Corresponding to sin 2θ=−25,there are two solutions.Talk to our academic expert!
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