The number of real roots of the equation esin x-e-sin x-4=0 are

Given equation esin x-e- sin x-4=0Let esin x=y,then given equation can be written asy2-4y-1=0⇒y=2±5But the value of y=esin x is always positive, soy=2+5 (∵2<5)⇒logey=loge(2+5)⇒sin x =loge(2+5)>1Which is impossible, since sin x cannot be greater than 1. Hence we cannot find any real value of x which satisfe the given equation