Number of real roots of the equation x+x−(1−x)=1 is
0
1
2
3
We have,
x+x−(1−x)=1⇒x−1−x=1−x
On squaring both sides, we get
x−1−x=1+x−2x⇒ −1−x=1−2x
Again, squaring on both sides, we get
1−x=1+4x−4x4x=5x⇒x=45 [on squaring both sides]⇒x=1625
Hence, the number of real solutions is 1.