The number of real roots of 32x2−7x+7=9 is
0
1
2
4
Given that, 32x2−7x+7=32⇒2x2−7x+7=2⇒ 2x2−7x+5=0Now, D=b2−4ac=(−7)2−4×2×5=49−40=9>0Hence, it has two real roots.