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Q.

The number of real roots ofx−1x+14−13x−1x+12+36=0,x≠−1 is

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a

0

b

2

c

3

d

4

answer is D.

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Detailed Solution

Put x−1x+12=y to obtainy2−13y+36=0⇒y=4,9∴x−1x+1=±2,±3Thus, the given equation has four real roots.

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