The number of real roots of (x−1)2+(x−2)2+(x−3)2=0  is

The given equation is (x−1)2+(x−2)2+(x−3)2=0 Since (x−1)2,(x−2)2,(x−3)2  can’t vanish simultaneously for any real x ,For example, put x=1⇒(1−1)2+(1−2)2+(1−3)2=5≠0 ∴  Number of real roots is 0.