Q.

The number of real solution of 2sin2⁡x+52cos2⁡x=7 is

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a

zero

b

1

c

finitely many

d

infinitely many

answer is D.

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Detailed Solution

Put 2sin2⁡x=t so that equation becomes t+5×2t=7⇒t2−7t+10=0⇒t=2,5But 1≤t≤2 Thus sin2⁡x=1
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