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The number of real solutions of the equation $\sin x = 2^{x} + 2^{- x}$ is zero then

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sinx≤1

sinx≥1

cosx=0

cosx<1

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detailed solution

Correct option is A

The 2x+2−x≥2 ⇒sinx≥2 which has no real solution ( ∵sinx≤1)

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The number of real solutions of the equation sinx=2x+2−xis zero then

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The number of real solutions of the equation $\sin x = 2^{x} + 2^{- x}$ is zero then