The number of real solutions of the equation x2+x+1x−1=2 +1x−1 is

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None of these

answer is A.

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Detailed Solution

The given equation is x2+x+1x−1 =2 +1x−1 ⇒ x2+x−2=0, x≠1⇒ x=−2, 1 but x=1 does not satisfy the given equation,therefore, x=−2 is the only root.

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