The number of real solutions of the equations tan−1x2−3x+2+cos−14x−x2−3=π is
one
two
zero
infinite
Since x2−3x+2≥0⇒tan−1x2−3x+2<π2
Since 4x−x2−3≥0⇒0<cos−14x−x2−3≤π2
⇒ 0 < L.H.S. < π
⇒ The given equation has no solution