The number of real solutions of log2x2+(x-1)log2x=6-2x is

let logx 2 =t⇒the given equation becomes t2+x-1t+2x-6=0⇒t+x-3t+2=0⇒log2x+x−3log2x+2=0 ⇒  logx 2 =3-x and log2x=-2 ⇒        x=2  and x=14⇒ number of solutions=2