The number of real value of x for which the equality 3x2+12x+6=5x+16 holds good is

Equation is 3x2+12x+6=5x+16    ...(i)when 3x2+12x+6≥0⇔x2+4x≥-2⇔x+22≥4-2⇔x+2≥(2)2⇔x+2≤-2 or x+2≥2    ...(ii)Then (i) becomes 3x2+12x+6=5x+16⇔3x2+7x-10=0⇒x=1, -103But x=-103 does not satisfy (ii).when 3x2+12x+6<0⇒x2+4x<-2⇒x+2≤2⇒-2-2≤x≤-2+2  ...(iii)Then (i) becomes ⇒3x2+12x+6=-(5x+16)⇒3x2+17x+22=0⇒x=-2, -113But x=-113 does not satisfy (iii). So, 1 and -2 are the only solutions.