Number of real values of x satisfying the equation log2x2−xlog2x−1x+log2x2=4 is
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a
0
b
2
c
3
d
7
answer is B.
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Detailed Solution
We have log2x2−xlog2x−1x+log2x2=4⇒ [log(x−1)+logx][log(x−1)−logx]+log2x2=4⇒ log2(x−1)2−log2x2+log2x2−4=0⇒ log2(x−1)2=4⇒ log2(x−1)=±2⇒ x−1=4 or 14⇒ x=5 or 54