The number of roots of the equation (x+2)(x−5)(x−3)(x+6)=  x−2x+4  is

Given equation is (x+2)(x−5)(x−3)(x+6)=  x−2x+4 ⇒    (x+2)  (x−5)  (x+4) =  (x−2)(x−3)(x+6)⇒  x3+x2−22x−40  =x3+x2−24x  +36⇒    2x=76  ⇒  x=38.∴  the number of roots of given equation is 1.