Q.

The number of solution of log 5+log (x2+1)log (x-2)=2 is

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a

2

b

3

c

1

d

None of these

answer is D.

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Detailed Solution

We have log 5+log (x2+1)log (x-2)=2⇒log {5(x2+1)}=log (x-2)2⇒5(x2+1)=(x-2)2  ⇒4x2+4x+1=0⇒x=-12Bur for x=-12log (x-2) is not meaningful.Hence it has no root.
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