Q.

Number of solution of secxcos5x+1=0where0

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a

4

b

1

c

3

d

2

answer is D.

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Detailed Solution

We have secxcos5x+1=0 ⇒1cosxcos5x+1=0 ⇒cos5x+cosx=0 ⇒2cos3xcos2x=0 ⇒cos3x=0, cos2x=0 ⇒3x=2n+1π2, 2x=2n+1π2 ⇒x=π6,π4∵0
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