The number of solutions of the equation 2sin−1x2−x+1+cos−1x2−x=3π2 is
0
infinite
2
4
sin–1x, cos–1x are defined for x ≤ 1 and x ≥ 0
∴x2−x+1<1 and x2−x>0⇒x2−x≤0 and x2−x≥0⇒x2−x=0⇒x=1,0
∴ There are two solutions, both satisfy the equation.