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Questions  

The number of solutions of the equation sin3 xcos x+sin2 xcos2x+sin xcos3x=1in the interval [0,2π] is/ are 

a
0
b
2
c
3
d
infinite

detailed solution

Correct option is A

sin3⁡xcos⁡x+sin2⁡xcos2⁡x+sin⁡xcos3⁡x=1or  sin⁡xcos⁡xsin2⁡x+sin⁡xcos⁡x+cos2⁡x=1or  sin⁡2x21+sin⁡2x2=1or  sin⁡2x(2+sin⁡2x)=4or  sin2⁡2x+2sin⁡2x−4=0or sin⁡ 2x=−2±4+162=−1±5This is not possible since −1≤sin⁡ 2x≤1Hence, the given equation has no solution.

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