The number of solutions of the equation sin3 xcos x+sin2 xcos2x+sin xcos3x=1in the interval [0,2π] is/ are
0
2
3
infinite
sin3xcosx+sin2xcos2x+sinxcos3x=1or sinxcosxsin2x+sinxcosx+cos2x=1or sin2x21+sin2x2=1or sin2x(2+sin2x)=4or sin22x+2sin2x−4=0or sin 2x=−2±4+162=−1±5This is not possible since −1≤sin 2x≤1Hence, the given equation has no solution.