Questions
The number of solutions of the equation in the interval [0,2] is/ are
detailed solution
Correct option is A
sin3xcosx+sin2xcos2x+sinxcos3x=1or sinxcosxsin2x+sinxcosx+cos2x=1or sin2x21+sin2x2=1or sin2x(2+sin2x)=4or sin22x+2sin2x−4=0or sin 2x=−2±4+162=−1±5This is not possible since −1≤sin 2x≤1Hence, the given equation has no solution.Talk to our academic expert!
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