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The number of solutions of the equation $2 {(\sin^{- 1} x)}^{2} - 5 \sin^{- 1} x + 2 = 0$ is

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Correct option is B

We have 2sin-1x2-5sin-1x+2=0 ⇒2sin-1x-1sin-1x-2=0 ⇒2sin-1x-1=0 ∵-π2≤sin-1x≤π2⇒sin-1x-2≠0 ⇒x=sin12 is the only solution of the equation

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The number of solutions of the equation 2(sin−1x)2−5sin−1x+2=0 is

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The number of solutions of the equation $2 {(\sin^{- 1} x)}^{2} - 5 \sin^{- 1} x + 2 = 0$ is