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$The number of solutions of the equation \sin^{2} \frac{x}{2} \cdot \sin x + 1 = 0 is$

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detailed solution

Correct option is D

sin2x2=−1sinx⇒1−cos2x2=−1sinx⇒sinxcosx=2+sinx⇒sin2x=4+2sinx∴ No solution

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The number of solutions of the equation sin2x2·sinx+1=0 is

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$The number of solutions of the equation \sin^{2} \frac{x}{2} \cdot \sin x + 1 = 0 is$