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The number of Solutions of the equation $T a n^{- 1} (x - 1) + T a n^{- 1} x + T a n^{- 1} (x + 1) = T a n^{- 1} (3 x)$ is /are

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Correct option is B

We have Tan-1x-1+Tan-1x+Tan-1x+1=Tan-13x⇒Tan−1x−1+Tan−1x+1=Tan−13x−Tan−1x⇒Tan-1x-1+x+11-x-1x+1=Tan-13x-x1+3xx ⇒2x2-x2=2x1+3x2 ⇒2x1+3x2-2+x2=0 ⇒x=0,x2=14 ⇒x=0, x=±12

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The number of Solutions of the equation Tan−1x−1+Tan−1x+Tan−1x+1=Tan−13xis /are

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The number of Solutions of the equation $T a n^{- 1} (x - 1) + T a n^{- 1} x + T a n^{- 1} (x + 1) = T a n^{- 1} (3 x)$ is /are