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Questions  

Number of solutions of the equation tanx+secx=2cosx in the interval  [0,2π] is

a
0
b
1
c
2
d
3

detailed solution

Correct option is C

sinx+1cosx=2cosx                       (cosx≠0)⇒2sin2x+sinx−1=0⇒(2sinx−1)(sinx+1)=0, ⇒sinx=12but sinx+1≠0     ∵cosx≠0)⇒x=π6,5π6 in [0,2π]

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