The number of solutions to the equation tan−1x3+tan−1x2=tan−1xis
3
2
1
0
tan−1x3+tan−1x2=tan−1x
Or tan−1x/3+x/21−x2/6=tan−1x
⇒5x6−x2=x
⇒x=0 or x2−1=0⇒x=±1Therefore, x={−1,0,1}⇒3 solutions