The number of solutions of log4(x−1) = log2(x−3)  is

Given condition is log4(x−1)=  log2(x−3) ⇒  log22(x−1)  =  log2(x−3) ⇒ 12  log2  (x−1)  =  log2(x−3)            (∵  loganm=1nlogam) ⇒ log2  (x−1) 12 =  log2(x−3) ⇒ log2x−1  =log2(x−3) ⇒ x−1=x−3,  x>3     squaring on both sides, we get⇒ x2−7x+10=0   ⇒(x−2)(x−5)=0  ∴   x=5.     (∵x>3  )∴  The number of solutions of given condition is ‘1’.