Q.
The number of solutions of the pair of equations 2sin2θ−cos2θ=0 and 2cos2θ−3sinθ=0 in the interval [0, 2π] is
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a
0
b
1
c
2
d
4
answer is C.
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Detailed Solution
2sin2θ−cos2θ=0⇒ 2sin2θ−1+2sin2θ=0⇒ sinθ=±122cos2θ−3sinθ=0⇒ 2sin2θ+3sinθ−2=0⇒ sinθ=12 or −2∴ sin θ=12 (common values)⇒ θ=π6, 5π6 (∴θ∈[0, 2π])
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