Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The number of solutions of the pair of equations 2sin2⁡θ−cos⁡2θ=0 and 2cos2⁡θ−3sin⁡θ=0 in the interval [0, 2π] is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

0

b

1

c

2

d

4

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

2sin2⁡θ−cos⁡2θ=0⇒ 2sin2⁡θ−1+2sin2⁡θ=0⇒ sin⁡θ=±122cos2⁡θ−3sin⁡θ=0⇒ 2sin2⁡θ+3sin⁡θ−2=0⇒ sin⁡θ=12 or −2∴ sin⁡ θ=12 (common values)⇒ θ=π6, 5π6               (∴θ∈[0, 2π])
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
The number of solutions of the pair of equations 2sin2⁡θ−cos⁡2θ=0 and 2cos2⁡θ−3sin⁡θ=0 in the interval [0, 2π] is