The number of solutions of ∑r=15 cosrx=5 in the interval [0,2π] is
0
2
5
10
∑r=15 cosrx=5⇒ cosx+cos2x+cos3x+cos4x+cos5x=5
which is possible only when cosx= cos 2x= cos3x= cos 4x= cos5x = 1 and is satisfied by x = 0 and x = 2π