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The number of solutions of $\sec x - \tan x = \sqrt{3}, x \in [0, 3 π]$ is

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Correct option is D

We have secx−tanx=3⇒secx+tanx=13Adding 2secx=3+13=43⇒secx=23>0Subtracting, we get 2tanx=13−3=−23⇒tanx=−13<0⇒x belongs to 4th quadrant⇒x=11π6,23π6

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The number of solutions of secx−tanx=3,x∈[0,3π] is

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The number of solutions of $\sec x - \tan x = \sqrt{3}, x \in [0, 3 π]$ is