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Number of solutions of $\sin \{x\} = \cos \{x\}$ in $[0, 2 π]$ is (Here $\{x\}$ is fractional part of x)

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Correct option is B

We have sinx=cosx⇒tanx=1⇒x=π4or5π4⇒x=π4⇒x=0.78,1.78,2.78,3.78,4.78,5.78

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Number of solutions of sinx=cosx in 0,2π is (Here x is fractional part of x)

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Number of solutions of $\sin \{x\} = \cos \{x\}$ in $[0, 2 π]$ is (Here $\{x\}$ is fractional part of x)