Number of terms in the sequence 1, 3, 6, 10, 15, …, 5050 is
50
75
100
125
Let,S=1+3+6+10+15+,…,+tn (1)
then S=1+3+6+10+,…,+tn−1+tn (2)
(1)−(2)⇒0=(1+2+3+4+… to n terms )−tn⇒ tn=n(n+1)2
Given, 5050=n(n+1)2⇒n2+n−10100=0
⇒ n=−1±1+404002=−1±404012=−1±2012=−101,100
∴ n=100. (∵ n is a positive integer)