The number of times the digit 3 will be written when listing the integers from 1 to 1000 is
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a
269
b
300
c
271
d
302
answer is B.
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Detailed Solution
Any number between 1 to 999 is a 3,digit number xyz where the digits xyz are any digits from 0 to 9.are any digits from 0 to 9.Now, we first count the numbers in which 3 occurs onceonly- Since, 3 can occur at one place in 3C1, ways, thereare 3C1⋅(9×9)=3⋅92 such numbers3C192+2×3C2×9+3×3c3=243+54+3=300