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The number of triangles that can be formed by 5 points in a line and 3 points on a parallel Iine is

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a
8C3
b
8C3−5C3
c
8C3−5C3−1
d
None of these

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detailed solution

Correct option is C

The triangle will be formed by joining any three non-collinear points.Required number of ways =8C3−5C3−3C3=8C3−5C3−1


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