The number of triangles that can be formed by 5 points in a line and 3 points on a parallel Iine is
8C3
8C3−5C3
8C3−5C3−1
None of these
The triangle will be formed by joining any three non-collinear points.Required number of ways
=8C3−5C3−3C3=8C3−5C3−1