The number of triangles that the four lines y=x+3, y=2x+3, y=3x+2 and y+x=3 form is
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a
4
b
2
c
3
d
1
answer is C.
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Detailed Solution
The lines y=x+3, y=2x+3 and y+x=3 are concurrent at 0,3.Rough sketch of the lines is as shown in the figure.From the figure, three triangles ABD,ABC and ACD can be formed