The number of value of 'k'for which the linear equations 4x+ky+2z=0,kx+4y+z=0, 2x+2y+z=0 possess a non-zero solution is

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answer is C.

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Detailed Solution

The system of equations will have a non-zero solution if4k2k41221=0⇒4(4-2)-k(k-2)+2(2k-8)=0⇒k2-6k+8=0⇒k=2,4

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