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The number of value of k, for which the system of equation has no solution is
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a
infinite
b
1
c
2
d
3
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Correct option is D
Condition for the system of equations has no solution is a1a2=b1b2≠c1c2∴ k+1k=8k+3≠4k3k−1 Take k+1k=8k+3⇒k2+4k+3=8k⇒k2−4k+3⇒(k−1)(k−3)=0k=1,3 If k=1, then 81+3≠4.12, false And __ if k=3, then 86≠4.39−1, true Therefore , k=3 Hence , only one value of k exist.Similar Questions
The number of solutions of
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