Number of values of c for which set (x,y):x2+y2+2x≤1∩{(x,y):x−y+c≥0} contains only one element
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a
One
b
Two
c
Zero
d
More than two
answer is A.
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Detailed Solution
x2+y2+2x≤1⇒x+12+y2≤22 It represents interior and boundary of the circle having centre at -1,0 and radius 2since the given two regions have only one point common ⇒the line x - y +c =0 is tangent of the circle. The perpendicular distance from centre to the line = radius −1+c2=2⇒c=3;c=−1Reject c=3 ( since number of common points are infinity ). If c=−1⇒ number of common points is =1 .