The number of values of k , for which the system of equations  (k+1)x+8y=4k;  kx+(k+3)y=3k−1  has infinitely ,many solutions is

The given system of equations are (k+1)x+8y=4k  and kx+(k+3)y=3k−1 Given that, the system of equations has infinitely many solutions, Then k+1k=8k+3=4k3k−1 k+1k=4k3k−1     or  8k+3=4k3k−1      After simplification we get k=1