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The number of values of K for which the system of equations (k+1)x+8y=4k,   kx+(k+3)y=3k1has no solution, is

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a
2
b
3
c
Infinite
d
1

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detailed solution

Correct option is D

For no solution, k+1k=8k+3≠4k3k−1→(1)⇒(k+1) (k+3) =8k⇒k=1,  3But for k=1,equation (1) is not satisfied         Hencek=3


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