The number of values of θ in 0,3π satisfying sin3θ−cos3θ+1+3sinθcosθ=0
2
3
4
5
We have sin3θ+−cosθ3+1=3sinθ−cosθ.1
⇒sinθ−cosθ+1=0 (∵a3+b3+c3=3abc ⇒a+b+c=0 or a=b=c)
⇒cosθ−sinθ=1⇒12cosθ−12sinθ=12,
⇒cosθ+π4=cosπ4
⇒θ+π4=2nπ±π4
⇒θ=2nπ or 2nπ−π2
⇒θ=0,2π,3π2