First slide
Algebra of complex numbers
Question

The number of values of θ(0,π] , such that (cosθ+isinθ)(cos3θ+isin3θ)(cos5θ+isin5θ)(cos7θ+isin7θ)(cos9θ+isin9θ)=1

is

Moderate
Solution

Using (cosα+isinα)(cosβ+isinβ)=cos(α+β)+isin(α+β)

We get

cos(25θ)=1, sin(25θ)=0 25θ=(2k+1)π,kI.

Now, 0<(2k+1)π25π 1(2k+1)25 k=0,1,2,,12

 

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