The number of values of θ∈(0,π] , such that (cosθ+isinθ)(cos3θ+isin3θ)(cos5θ+isin5θ)(cos7θ+isin7θ)(cos9θ+isin9θ)=−1
is
11
13
14
16
Using (cosα+isinα)(cosβ+isinβ)=cos(α+β)+isin(α+β)
We get
cos(25θ)=−1, sin(25θ)=0⇒ 25θ=(2k+1)π,k∈I.
Now, 0<(2k+1)π25≤π⇒ 1≤(2k+1)≤25⇒ k=0,1,2,…,12