First slide
Trigonometric equations
Question

The number of values of x in the interval [0,3π] satisfying the equation 2sin2x+5sinx3=0 is

Moderate
Solution

We have (sinx+3)(2sinx1)=0

 sinx=3 which is not possible

or sinx=1/2x=π/6,5π/6,13π/6,17π/6 as x[0,3π]

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