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The number of values of x in the interval $[0, 3 π]$ satisfying the equation $2 \sin^{2} x + 5 \sin x - 3 = 0$ is

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Correct option is B

We have (sin⁡x+3)(2sin⁡x−1)=0⇒ sin⁡x=−3 which is not possibleor sin⁡x=1/2⇒x=π/6,5π/6,13π/6,17π/6 as x∈[0,3π]

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The number of values of x in the interval [0,3π] satisfying the equation 2sin2⁡x+5sin⁡x−3=0 is

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The number of values of x in the interval $[0, 3 π]$ satisfying the equation $2 \sin^{2} x + 5 \sin x - 3 = 0$ is