Number of values of x lying in the interval [0, 5π] and satisfying the equation sinx=tanx is.
5
6
9
12
sinx=tanx⇒sinx(cosx−1)=0
⇒ sinx=0 or cosx=1
However when , cosx=1, then sinx=0
∴sinx=0⇒x=0,π,2π,3π,4π,5π