The number of ways of arranging 20 boys so that 3 particular boys are separated is
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a
9(16!)
b
15(16!)
c
15(17!)/2
d
none of these
answer is D.
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Detailed Solution
We can arrange remaining 17 boys in 17! ways. For 3 particular boys we have 18 positions. We can arrange3 particulars boys at these places in 18P3 ways. Thus, the required number of ways=(17!) 18P3=17!18!15!