The number of ways of choosing a committee of two women and three men from five women and six men, if Mr. A refuses to serve on the committee if Mr. B is a member and Mr. B can only serve, if Ms. C is the member of the committee is

(i) Ms. C is taken     (A) B included ⇒ A excluded ⇒ 4C1×4C2=24     (B) B excluded ⇒  4C1×5C3=40(ii) Ms. C is not taken⇒ B does not come ⇒ 4C2×5C3=60 ⇒ Total = 124Alternate method:Case I:Mr. B is present⇒ A is excluded and C includedHence, the number of ways is  4C24C1=24.Case II:Mr. B is absent⇒ No constraintHence, the number of ways is  5C35C2=100.∴ Total = 124