Questions
The number of ways of selecting cards of an ordinary pack of playing cards so that exactly of them
are of the same denomination is
Remember concepts with our Masterclasses.
80k Users 60 mins Expert Faculty Ask Questions
a
2496
b
13C3×4C3×48
c
52C3×48
d
none of these
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is A
We can choose one denomination in 13C1 ways, then 3 cards of this denomination can be chosenin 4C3 ways and one remaining card can be chosen in 48C1 ways. Thus, the total number of choices is 13C1 4C3 48C1=13×4×48=2496.Similar Questions
is equal to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
