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The number of ways in which 10 candidates A1,A2,,A10 can be ranked such that A1, is always above A10 is

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a
5!
b
2(5!)
c
10!
d
1210!

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detailed solution

Correct option is D

Two positions for A1, and A10 can be selected in  10C2 ways. Rest eight students can be ranked in 8! ways.Hence, total number of ways is   10C2×8!=(1/2)(10!)


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